x^2+11x=28=0

Solution for x^2+11x=28=0 equation:

x^2+11x=28=0

We move all terms to the left:

x^2+11x-(28)=0

a = 1; b = 11; c = -28;
Δ = b2-4ac
Δ = 112-4·1·(-28)
Δ = 233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{233}}{2*1}=\frac{-11-\sqrt{233}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{233}}{2*1}=\frac{-11+\sqrt{233}}{2}
$